Aptitiude Questions Y2

11. Vivek travelled 1200km by air which formed 2/5 of his trip.One third of the whole trip , he travelled by car and the rest of the journey he performed by train. The distance travelled by tain was???

Ans.800km



Sol: Let the total trip be x km.

Then 2x/5=1200

x=1200*5/2=3000km

Distance travelled by car =1/3*3000=1000km

Journey by train =[3000-(1200+1000)]=800km.









12. In a college ,1/5 th of the girls and 1/8 th of the boys took part in a social camp.What of the total number of students in the college took part in the camp?

Ans: 2/13



Sol: Out of 5 girls 1 took part in the camp

out of 8 boys 1 took part in the camp

so, out of 13 students 2 took part in the camp.

So, 2/13of the total strength took part in the camp.



13. On sports day,if 30 children were made to stand in a column,16 columns could be formed. If 24 children were made to stand in a column , how many columns could be formed?

Ans. 20


Sol: Total number of children=30*16=480

Number of columns of 24 children each =480/24=20.



14. Two trains 200mts and 150mts are running on the parallel rails at this rate of 40km/hr and 45km/hr.In how much time will they cross each other if they are running in the same direction.



Ans: 252sec



Sol: Relative speed=45-40=5km/hr=25/18 mt/sec

Total distance covered =sum of lengths of trains =350mts.

So, time taken =350*18/25=252sec.



15. 5/9 part of the population in a village are males. If 30% of the males are married, the percentage of unmarried females in the total population is:



Ans: (250/9)%



Sol: Let the population =x Males=(5/9)x

Married males = 30% of (5/9)x = x/6

Married females = x/6

Total females = (x-(5/9)x)=4x/9

Unmarried females = (4x/9 – x/6) = 5x/18

Required percentage = (5x/18 * 1/x * 100) = (250/9)%



16. From height of 8 mts a ball fell down and each time it bounces half the distnace back. What will be the distance travelled



Ans.: 24

Sol. 8+4+4+2+2+1+1+0.5+0.5+ and etc .. =24



17. First day of 1999 is sunday what day is the last day

Ans.: Monday

18. Increase area of a square by 69% by what percent should the side be incresed

Ans.: 13

Sol:Area of square=x2

Then area of increase=100+69=169

square root of 169 i.e 13 .



19. Ten years ago, chandrawathi’s mother was four times older than her daughter. After 10years, the mother will be twice older than daughter. The present age of Chandrawathi is:



Ans.20 years


Sol: Let Chandrawathi’s age 10 years ago be x years.
Her mother’s age 10 years ago = 4x

(4x+10)+10=2(x+10+10)

x=10

Present age of Chandrawathi = (x+10) = 20years



20. Finding the wrong term in the given series

7, 28, 63, 124, 215, 342, 511

Ans:28



Sol: Clearly, the correct sequence is

2^3 – 1, 3^3 – 1, 4^3 – 1, 5^3 – 1, ……….

Therefore, 28 is wrong and should be replaced by (3^3 – 1) i.e, 26.